Optimal. Leaf size=263 \[ \frac{a^2 2^{-m-3} e^{2 e-\frac{2 c f}{d}} (c+d x)^m \left (-\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{2 f (c+d x)}{d}\right )}{f}+\frac{a^2 e^{e-\frac{c f}{d}} (c+d x)^m \left (-\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{f (c+d x)}{d}\right )}{f}-\frac{a^2 e^{\frac{c f}{d}-e} (c+d x)^m \left (\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{f (c+d x)}{d}\right )}{f}-\frac{a^2 2^{-m-3} e^{\frac{2 c f}{d}-2 e} (c+d x)^m \left (\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{2 f (c+d x)}{d}\right )}{f}+\frac{3 a^2 (c+d x)^{m+1}}{2 d (m+1)} \]
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Rubi [A] time = 0.341582, antiderivative size = 263, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3318, 3312, 3307, 2181} \[ \frac{a^2 2^{-m-3} e^{2 e-\frac{2 c f}{d}} (c+d x)^m \left (-\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{2 f (c+d x)}{d}\right )}{f}+\frac{a^2 e^{e-\frac{c f}{d}} (c+d x)^m \left (-\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{f (c+d x)}{d}\right )}{f}-\frac{a^2 e^{\frac{c f}{d}-e} (c+d x)^m \left (\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{f (c+d x)}{d}\right )}{f}-\frac{a^2 2^{-m-3} e^{\frac{2 c f}{d}-2 e} (c+d x)^m \left (\frac{f (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{2 f (c+d x)}{d}\right )}{f}+\frac{3 a^2 (c+d x)^{m+1}}{2 d (m+1)} \]
Antiderivative was successfully verified.
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Rule 3318
Rule 3312
Rule 3307
Rule 2181
Rubi steps
\begin{align*} \int (c+d x)^m (a+a \cosh (e+f x))^2 \, dx &=\left (4 a^2\right ) \int (c+d x)^m \sin ^4\left (\frac{1}{2} (i e+\pi )+\frac{i f x}{2}\right ) \, dx\\ &=\left (4 a^2\right ) \int \left (\frac{3}{8} (c+d x)^m+\frac{1}{2} (c+d x)^m \cosh (e+f x)+\frac{1}{8} (c+d x)^m \cosh (2 e+2 f x)\right ) \, dx\\ &=\frac{3 a^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac{1}{2} a^2 \int (c+d x)^m \cosh (2 e+2 f x) \, dx+\left (2 a^2\right ) \int (c+d x)^m \cosh (e+f x) \, dx\\ &=\frac{3 a^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac{1}{4} a^2 \int e^{-i (2 i e+2 i f x)} (c+d x)^m \, dx+\frac{1}{4} a^2 \int e^{i (2 i e+2 i f x)} (c+d x)^m \, dx+a^2 \int e^{-i (i e+i f x)} (c+d x)^m \, dx+a^2 \int e^{i (i e+i f x)} (c+d x)^m \, dx\\ &=\frac{3 a^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac{2^{-3-m} a^2 e^{2 e-\frac{2 c f}{d}} (c+d x)^m \left (-\frac{f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac{2 f (c+d x)}{d}\right )}{f}+\frac{a^2 e^{e-\frac{c f}{d}} (c+d x)^m \left (-\frac{f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac{f (c+d x)}{d}\right )}{f}-\frac{a^2 e^{-e+\frac{c f}{d}} (c+d x)^m \left (\frac{f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac{f (c+d x)}{d}\right )}{f}-\frac{2^{-3-m} a^2 e^{-2 e+\frac{2 c f}{d}} (c+d x)^m \left (\frac{f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac{2 f (c+d x)}{d}\right )}{f}\\ \end{align*}
Mathematica [A] time = 1.0451, size = 302, normalized size = 1.15 \[ -\frac{a^2 2^{-m-5} e^{-2 \left (\frac{c f}{d}+e\right )} (c+d x)^m (\cosh (e+f x)+1)^2 \text{sech}^4\left (\frac{1}{2} (e+f x)\right ) \left (-\frac{f^2 (c+d x)^2}{d^2}\right )^{-m} \left (-d e^{4 e} (m+1) \left (f \left (\frac{c}{d}+x\right )\right )^m \text{Gamma}\left (m+1,-\frac{2 f (c+d x)}{d}\right )-d 2^{m+3} (m+1) e^{\frac{c f}{d}+3 e} \left (f \left (\frac{c}{d}+x\right )\right )^m \text{Gamma}\left (m+1,-\frac{f (c+d x)}{d}\right )+d 2^{m+3} (m+1) e^{\frac{3 c f}{d}+e} \left (-\frac{f (c+d x)}{d}\right )^m \text{Gamma}\left (m+1,\frac{f (c+d x)}{d}\right )+d (m+1) e^{\frac{4 c f}{d}} \left (-\frac{f (c+d x)}{d}\right )^m \text{Gamma}\left (m+1,\frac{2 f (c+d x)}{d}\right )-3 f 2^{m+2} (c+d x) e^{2 \left (\frac{c f}{d}+e\right )} \left (-\frac{f^2 (c+d x)^2}{d^2}\right )^m\right )}{d f (m+1)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.113, size = 0, normalized size = 0. \begin{align*} \int \left ( dx+c \right ) ^{m} \left ( a+a\cosh \left ( fx+e \right ) \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.29729, size = 1139, normalized size = 4.33 \begin{align*} -\frac{{\left (a^{2} d m + a^{2} d\right )} \cosh \left (\frac{d m \log \left (\frac{2 \, f}{d}\right ) + 2 \, d e - 2 \, c f}{d}\right ) \Gamma \left (m + 1, \frac{2 \,{\left (d f x + c f\right )}}{d}\right ) + 8 \,{\left (a^{2} d m + a^{2} d\right )} \cosh \left (\frac{d m \log \left (\frac{f}{d}\right ) + d e - c f}{d}\right ) \Gamma \left (m + 1, \frac{d f x + c f}{d}\right ) - 8 \,{\left (a^{2} d m + a^{2} d\right )} \cosh \left (\frac{d m \log \left (-\frac{f}{d}\right ) - d e + c f}{d}\right ) \Gamma \left (m + 1, -\frac{d f x + c f}{d}\right ) -{\left (a^{2} d m + a^{2} d\right )} \cosh \left (\frac{d m \log \left (-\frac{2 \, f}{d}\right ) - 2 \, d e + 2 \, c f}{d}\right ) \Gamma \left (m + 1, -\frac{2 \,{\left (d f x + c f\right )}}{d}\right ) -{\left (a^{2} d m + a^{2} d\right )} \Gamma \left (m + 1, \frac{2 \,{\left (d f x + c f\right )}}{d}\right ) \sinh \left (\frac{d m \log \left (\frac{2 \, f}{d}\right ) + 2 \, d e - 2 \, c f}{d}\right ) - 8 \,{\left (a^{2} d m + a^{2} d\right )} \Gamma \left (m + 1, \frac{d f x + c f}{d}\right ) \sinh \left (\frac{d m \log \left (\frac{f}{d}\right ) + d e - c f}{d}\right ) + 8 \,{\left (a^{2} d m + a^{2} d\right )} \Gamma \left (m + 1, -\frac{d f x + c f}{d}\right ) \sinh \left (\frac{d m \log \left (-\frac{f}{d}\right ) - d e + c f}{d}\right ) +{\left (a^{2} d m + a^{2} d\right )} \Gamma \left (m + 1, -\frac{2 \,{\left (d f x + c f\right )}}{d}\right ) \sinh \left (\frac{d m \log \left (-\frac{2 \, f}{d}\right ) - 2 \, d e + 2 \, c f}{d}\right ) - 12 \,{\left (a^{2} d f x + a^{2} c f\right )} \cosh \left (m \log \left (d x + c\right )\right ) - 12 \,{\left (a^{2} d f x + a^{2} c f\right )} \sinh \left (m \log \left (d x + c\right )\right )}{8 \,{\left (d f m + d f\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \cosh \left (f x + e\right ) + a\right )}^{2}{\left (d x + c\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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